# FLK100

Flask app appears to be run with debug=True, which exposes the Werkzeug debugger and allows the execution of arbitrary code.

## Example

The following code will raise this warning:

```python
from flask import Flask

app = Flask(__name__)
app.run(debug=True)
```

## See Also

* [Flask Documentation](https://flask.palletsprojects.com/en/1.1.x/quickstart/#debug-mode)