type type A = "@foo" | "@bar" | "/foo" | "/bar"A = '@foo' | '@bar' | '/foo' | '/bar' const a: type A = "@foo" | "@bar" | "/foo" | "/bar"A = '@@foo@bar'Type '"@"' is not assignable to type 'A'.
type A = "@foo" | "@bar" | "/foo" | "/bar"